Articles
Register
Sign In
Search
Michonne15
@Michonne15
January 2021
1
51
Report
Bonsoir, je bloque sur une question, la 3. Je n'y arrive pas du tout, pouvez-vous m'aider s'il vous plaît?
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
scoladan
Verified answer
Bonjour,
f(x) = 2x³ - x² - 9x - 6
1) f(-1) = -2 - 1 + 9 - 6 = 0
2) (x + 1)(ax² + bx + c)
= ax³ + (a + b)x² + (c + b)x + c
Par analogie des termes de même degré :
a = 2
a + b = -1
b + c = -9
c = -6
soit a = 2, b = -3 et c = -6
⇒ f(x) = (x+1)(2x² - 3x - 6)
3) f(x) = 0
⇔ x = -1 ou 2x² - 3x - 6 = 0
Δ = (-3)² - 4x2x(-6) = 9 + 48 = 57
donc 2 autres solutions :
x = (3 - √57)/4 soit environ -1,137
et x = (3 + √57)/4 soit environ 2,637
Et donc f(x) = (x+1)(x - (3 - √57)/4)(x - (3 + √57)/4)
1 votes
Thanks 1
More Questions From This User
See All
Michonne15
January 2021 | 0 Respostas
Responda
Michonne15
January 2021 | 0 Respostas
Responda
Michonne15
January 2021 | 0 Respostas
Responda
Michonne15
January 2021 | 0 Respostas
Responda
Michonne15
January 2021 | 0 Respostas
Responda
Michonne15
January 2021 | 0 Respostas
Responda
Michonne15
January 2021 | 0 Respostas
Responda
Michonne15
January 2021 | 0 Respostas
Responda
Michonne15
January 2021 | 0 Respostas
Responda
Michonne15
January 2021 | 0 Respostas
Responda
×
Report "Bonsoir, je bloque sur une question, la 3. Je n'y arrive pas du tout, pouvez-vous m'aider s'il vous .... Pergunta de ideia de Michonne15"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonjour,f(x) = 2x³ - x² - 9x - 6
1) f(-1) = -2 - 1 + 9 - 6 = 0
2) (x + 1)(ax² + bx + c)
= ax³ + (a + b)x² + (c + b)x + c
Par analogie des termes de même degré :
a = 2
a + b = -1
b + c = -9
c = -6
soit a = 2, b = -3 et c = -6
⇒ f(x) = (x+1)(2x² - 3x - 6)
3) f(x) = 0
⇔ x = -1 ou 2x² - 3x - 6 = 0
Δ = (-3)² - 4x2x(-6) = 9 + 48 = 57
donc 2 autres solutions :
x = (3 - √57)/4 soit environ -1,137
et x = (3 + √57)/4 soit environ 2,637
Et donc f(x) = (x+1)(x - (3 - √57)/4)(x - (3 + √57)/4)