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Lele8253000
@Lele8253000
May 2019
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Bonsoir je dois faire un dm physique chimie et je ne comprend pas qqln peut m’aider c’est à faire bon pour dem je suis un élève de ES
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scoladan
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Bonjour,
1)
NaOH(s) + H₂O(l) → Na⁺(sol) + HO⁻(sol)
2) ions Na⁺ et ions HO⁻
3) m(NaOH) = 5g
M(NaOH) = M(Na) + M(O) + M(H) = 23 + 16 + 1 = 40 g.mol⁻¹
⇒ n(NaOH) = m(NaOH)/M(NaOH) = 5/40 = 0,125 mol
4) Cm = m/V = 5/500.10⁻³ = 5/0,500 = 10 g.L⁻¹
soit 10 g pour 1000 g de solution = 10/1000 = 1%
5) D'après l'équation de la réaction, n(HO⁻) = n(NaOH)
donc n(HO⁻) = 0,125 mol
6) C = n(HO⁻)/V = 0,125/0,5 = 0,25 mol.L⁻¹
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scoladan
non, non ;)
scoladan
J'ai bugué hier soir : NaOH + H2O --> Na+ + HO- + H2O, ça ne change pas la suite car en fait on peut simplifier en écrivant simplement NaOH --> Na+ + HO-, mais c'est plus correct.
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Lista de comentários
Verified answer
Bonjour,1)
NaOH(s) + H₂O(l) → Na⁺(sol) + HO⁻(sol)
2) ions Na⁺ et ions HO⁻
3) m(NaOH) = 5g
M(NaOH) = M(Na) + M(O) + M(H) = 23 + 16 + 1 = 40 g.mol⁻¹
⇒ n(NaOH) = m(NaOH)/M(NaOH) = 5/40 = 0,125 mol
4) Cm = m/V = 5/500.10⁻³ = 5/0,500 = 10 g.L⁻¹
soit 10 g pour 1000 g de solution = 10/1000 = 1%
5) D'après l'équation de la réaction, n(HO⁻) = n(NaOH)
donc n(HO⁻) = 0,125 mol
6) C = n(HO⁻)/V = 0,125/0,5 = 0,25 mol.L⁻¹