bonjour
(2x+3)² = 81
(2x+3)² - 81 = 0
(2x+3+9) (2x+3-9) = 0
(2x+12) (2x-6) = 0
soit 2x+12 = 0 => x = -6
soit 2x-6 = 0 => x = 3
√(5x-3) = 8
=> 5x-3 = 8²
5x = 64 + 3
x = 67/5
ex 2
x/2x+1 = 1
donc x = 1 * (2x+1) produit en croix
x = 2x + 1
x = - 1
2 / (x-2) = 3 / (x-3)
=> 2 (x-3) = 3 (x-2)
je te laisse terminer
:)
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bonjour
(2x+3)² = 81
(2x+3)² - 81 = 0
(2x+3+9) (2x+3-9) = 0
(2x+12) (2x-6) = 0
soit 2x+12 = 0 => x = -6
soit 2x-6 = 0 => x = 3
√(5x-3) = 8
=> 5x-3 = 8²
5x = 64 + 3
x = 67/5
ex 2
x/2x+1 = 1
donc x = 1 * (2x+1) produit en croix
x = 2x + 1
x = - 1
2 / (x-2) = 3 / (x-3)
=> 2 (x-3) = 3 (x-2)
je te laisse terminer
:)