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May 2019
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Bonsoir pouvez vous m'aider à cet exercice s'il vous plaît :)
DÉVELOPPER et RÉDUIRE
a=(2y+1)(y+3) b=(y-5)(y-2)
c=(4a+3)(3a+2) d=(3-2a)(a+1)
Merci de votre aide
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Commentaires (1)
Bonsoir
A = 2 y² + 6 y + y + 3 =
2 y² + 7 y + 3
B = y² - 2 y - 5 y + 10 =
y² - 7 y + 10
C = 12 a² + 8 a + 9 a + 6 =
12 a² + 17 a + 6
D = 3 a + 3 - 2 a² - 2 a =
- 2 a² + a + 3
2 votes
Thanks 1
base
Mercii
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A = 2 y² + 6 y + y + 3 = 2 y² + 7 y + 3
B = y² - 2 y - 5 y + 10 = y² - 7 y + 10
C = 12 a² + 8 a + 9 a + 6 = 12 a² + 17 a + 6
D = 3 a + 3 - 2 a² - 2 a = - 2 a² + a + 3