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charline661
@charline661
January 2021
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BonSoir
Pouvez vous m'aider s'il vous plaît ? Merci
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scoladan
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Bonjour,
Acidulés Guimauve Total
Orange 10 18 28
Fraise 30 42 72
Total 40 60 100
1)
p(A) = 40/100 = 2/5
p(G) = 60/100 = 3/5
p(A∩O) = 10/100 = 1/10
pG(O) = p(G∩O)/p(G) = (18/100)/(60/100) = 3/10
2) pA(O) = p(A∩O)/p(A) = (1/10)/(2/5) = 1/4
p(G∩O) = 18/100 = 9/50
1 votes
Thanks 1
charline661
10/100? J'aurais mis 10/40
charline661
Et aussi 18/60 pas sur 100
charline661
Je comprends pas
charline661
Car sur 40 bonbons acidulé il y'a 10 bonbons parfum orange
charline661
De meme pour la guimauve
scoladan
Le tableau donne des quantités, pas des probas. Il y a bien 10 acidulés orange, sur un total de 100
charline661
Ah d'accord donc c'est tjrs sur la totalité ?
scoladan
sauf pour les probabilités conditionnelles comme pA(O) dans cet exo par exp
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Verified answer
Bonjour,Acidulés Guimauve Total
Orange 10 18 28
Fraise 30 42 72
Total 40 60 100
1)
p(A) = 40/100 = 2/5
p(G) = 60/100 = 3/5
p(A∩O) = 10/100 = 1/10
pG(O) = p(G∩O)/p(G) = (18/100)/(60/100) = 3/10
2) pA(O) = p(A∩O)/p(A) = (1/10)/(2/5) = 1/4
p(G∩O) = 18/100 = 9/50