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Silent
@Silent
April 2019
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Bonsoir, pouvez-vous m'expliquer en détaille cette factorisation, je n'arrive pas à la comprendre.
(x -3) (-x-2)
E = (x-3)² + (x-3) (1-2x)
E = (x-3) (x-3+(1-2x)
E = (x-3) (-1x-2)
E = (x-3) (-x-2)
(Il n'y pas de multiplication, ce sont des X)
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Bonsoir,
E = (x - 3)² + (x - 3) (1 - 2x)
E = (x - 3)(x - 3) + (x - 3) (1 - 2x)
E =
(x - 3)
(x - 3) +
(x - 3)
(1 - 2x) (--> J'ai souligné le facteur commun)
E =
(x - 3)
[(x - 3) + (1 - 2x)] (--> j'ai mis (x-3) en facteur)
E =
(x - 3)
(x - 3 + 1 - 2x)
E = (x - 3) (x - 2x - 3 + 1)
E = (x - 3) (-1x - 2) (car x - 2x = -1x et -3 + 1 = -2)
E = (x - 3) (-x - 2) (car -1x = s'écrit -x)
1 votes
Thanks 1
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E = (x - 3)² + (x - 3) (1 - 2x)
E = (x - 3)(x - 3) + (x - 3) (1 - 2x)
E = (x - 3)(x - 3) + (x - 3) (1 - 2x) (--> J'ai souligné le facteur commun)
E = (x - 3) [(x - 3) + (1 - 2x)] (--> j'ai mis (x-3) en facteur)
E = (x - 3) (x - 3 + 1 - 2x)
E = (x - 3) (x - 2x - 3 + 1)
E = (x - 3) (-1x - 2) (car x - 2x = -1x et -3 + 1 = -2)
E = (x - 3) (-x - 2) (car -1x = s'écrit -x)