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Silent
@Silent
June 2021
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[FACTORISER]
Bonsoir, pouvez-vous me factoriser (entièrement) les
4 expressions
, s'il vous
plaît ?
Je vous remercie d'avance.
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isapaul
Verified answer
Bonsoir
A = (2x-7)² - 49
A = (2x-7)² - 7² Identité remarquable a²-b² = (a-b)(a+b)
A = (2x - 7 - 7)(2x - 7 + 7 )
A = (2x - 14)(2x)
B = (3x-3)(2x+7)-(9x²-9)
B = (3x-3)(2x+7)- ( (3x)² - 3² ) identité remarquable a²-b² = (a-b)(a+b)
B = (3x-3)(2x+7) - ( 3x-3)(3x+3) facteur commun (3x-3)
B = (3x-3)( 2x+7 - (3x+3))
B = (3x-3)( 2x+7 - 3x - 3)
B = 3x-3)(4-x)
C = 4(1-6x)(7x-2) + 9(x-3)(7x-2)
C = (4 - 24x)(7x-2) + (9x - 27)(7x - 2)
C = (7x-2)(4-24x+9x-27)
C = 7x - 2)( -15x - 23)
D = (5x-8)² - (2x+9)²
D = (5x - 8 - 2x - 9)( 5x - 8 + 2x + 9)
D = (3x - 17)( 7x + 1)
Bonne soirée
2 votes
Thanks 2
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Verified answer
BonsoirA = (2x-7)² - 49
A = (2x-7)² - 7² Identité remarquable a²-b² = (a-b)(a+b)
A = (2x - 7 - 7)(2x - 7 + 7 )
A = (2x - 14)(2x)
B = (3x-3)(2x+7)-(9x²-9)
B = (3x-3)(2x+7)- ( (3x)² - 3² ) identité remarquable a²-b² = (a-b)(a+b)
B = (3x-3)(2x+7) - ( 3x-3)(3x+3) facteur commun (3x-3)
B = (3x-3)( 2x+7 - (3x+3))
B = (3x-3)( 2x+7 - 3x - 3)
B = 3x-3)(4-x)
C = 4(1-6x)(7x-2) + 9(x-3)(7x-2)
C = (4 - 24x)(7x-2) + (9x - 27)(7x - 2)
C = (7x-2)(4-24x+9x-27)
C = 7x - 2)( -15x - 23)
D = (5x-8)² - (2x+9)²
D = (5x - 8 - 2x - 9)( 5x - 8 + 2x + 9)
D = (3x - 17)( 7x + 1)
Bonne soirée