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Vanesse1
@Vanesse1
May 2019
1
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Bonsoir tous le monde j'ai besoin d'aide pour un devoir de maths c'est pour demain SVP
voila l'énoncer: développer les expressions données
3x(1+2x)
4a(1-5x)
(1-2a)fois 3x
7y(-2x-5)
-5x(-x+6)
6x(5-3y)
merci d'avance
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chacha314
Verified answer
Salut !
3x(1+2x)
= 3x*(1+2x)
= 3x+3x*2x
=3x+6x²
4a(1-5x)
=4a-4a*5x
=4a-20aX
(1-2a)*3x
=3x*1 -2a*3x
=3x-6ax
7y (-2x-5x)
=7y*(-7x)
=-49xy
-5x (-x+6)
=-5x (-x)-5x*6
=5x²-30x
6x(5-3y)
=6x*5-6x*3y
=30x-18xy
2 votes
Thanks 1
vanesse1
les petites étoile a coté sont des signes de multiplications
chacha314
Oui :)
chacha314
Pour ne pas confondre avec les x
vanesse1
ok merci
chacha314
De rien :)
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Lista de comentários
Verified answer
Salut !3x(1+2x)
= 3x*(1+2x)
= 3x+3x*2x
=3x+6x²
4a(1-5x)
=4a-4a*5x
=4a-20aX
(1-2a)*3x
=3x*1 -2a*3x
=3x-6ax
7y (-2x-5x)
=7y*(-7x)
=-49xy
-5x (-x+6)
=-5x (-x)-5x*6
=5x²-30x
6x(5-3y)
=6x*5-6x*3y
=30x-18xy