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Zaitnacer
@Zaitnacer
May 2019
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Bonsoir vous pouvez m'aider svp
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AbderraoufSlamani
Bonsoir !!
1)
A = (1 + √2) / (2+√2)
A = (1 + √2)(2-√2) / (2+√2)(2-√2)
A = (2 + 2√2 - √2 - 2) / 2² - (√2)²
A = √2 / 4 - 2
A = √2 / 2 = (√2 × √2)/ (2 × √2) = 2 / 2√2
A = 1/√2
2)
B - A = ((4 + √2)/7) - 1/√2
B - A = ((4 + √2)√2 - 7)/7√2
B - A = (4√2 - 5)/7√2
B - A = ((4√2 - 5))√2/(7√2)√2
B - A = (8 - 5√2) /14
3)
5√2 = √(25 × 2) = √50
8 = √64
√64 > √50 donc 8 > 5√2 parce que 8 et 5√2 sont des nombres positif
4)
B - A égal à nombre positif ( 8 > 5√2 donc 8 - 5√2 > 0 ) donc B > A
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AbderraoufSlamani
de rien ^^
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Lista de comentários
1)
A = (1 + √2) / (2+√2)
A = (1 + √2)(2-√2) / (2+√2)(2-√2)
A = (2 + 2√2 - √2 - 2) / 2² - (√2)²
A = √2 / 4 - 2
A = √2 / 2 = (√2 × √2)/ (2 × √2) = 2 / 2√2
A = 1/√2
2)
B - A = ((4 + √2)/7) - 1/√2
B - A = ((4 + √2)√2 - 7)/7√2
B - A = (4√2 - 5)/7√2
B - A = ((4√2 - 5))√2/(7√2)√2
B - A = (8 - 5√2) /14
3)
5√2 = √(25 × 2) = √50
8 = √64
√64 > √50 donc 8 > 5√2 parce que 8 et 5√2 sont des nombres positif
4)
B - A égal à nombre positif ( 8 > 5√2 donc 8 - 5√2 > 0 ) donc B > A