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Assyao
@Assyao
April 2019
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Boujour j'ai un exo a faire mais je comprend rien .
Factoriser
En reconnaissant un facteur commun.
a)x*y+x*z
b) a*(b+4)+3*a
c) 5*(2t+1)+(2t+1)*(t-5)
d)5x²+6x
e) (x+1)² -3 (x+1)
merci
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a)x*y+x*z
=x(y+z)
b) a*(b+4)+3*a
=a(b+7)
c) 5*(2t+1)+(2t+1)*(t-5)
=(2t+1)(t)
d)5x²+6x
=x(5x+6)
e) (x+1)² -3 (x+1)
=(x+1)(x-2)
0 votes
Thanks 1
shanaclaes98
A) x(y+z)
b) a(b+4+3)=a(b+7)
c) (2t+1)(5+t-5)=(2t+1)t
d) x(5x+6)
e) (x+1)(x+1)-3=(x+1)(x+1-3)=(x+1)(x-2)
0 votes
Thanks 1
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EXERCICE 1 Le triangle ABC a pour hauteur AH .AB= 3.9cm AC= 6cm CH=4.8cmCalculer AH , BH puis l'aire du triangle ABC. merci
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Aidez moi svp je ne comprend rien . merci
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=x(y+z)
b) a*(b+4)+3*a
=a(b+7)
c) 5*(2t+1)+(2t+1)*(t-5)
=(2t+1)(t)
d)5x²+6x
=x(5x+6)
e) (x+1)² -3 (x+1)
=(x+1)(x-2)
b) a(b+4+3)=a(b+7)
c) (2t+1)(5+t-5)=(2t+1)t
d) x(5x+6)
e) (x+1)(x+1)-3=(x+1)(x+1-3)=(x+1)(x-2)