Resposta:
[tex]3^{2x+3}-3^{2x+2}+2\cdot3^{2x}=2^{2x+5}-2^{2x+1}\\\\\\3^{2x}(3^{3}-3^{2}+2)=2^{2x}(2^{5}-2^{1})\\\\\\3^{2x}(27-9+2)=2^{2x}(32-2)\\\\\\3^{2x}(20)=2^{2x}(30)\\\\\\\dfrac{3^{2x}}{2^{2x}}=\dfrac{30}{20}\to\left(\dfrac{3}{2}\right)^{2x}=\dfrac{3}{2}\to 2x = 1\to x=\dfrac{1}{2}[/tex]
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Resposta:
[tex]3^{2x+3}-3^{2x+2}+2\cdot3^{2x}=2^{2x+5}-2^{2x+1}\\\\\\3^{2x}(3^{3}-3^{2}+2)=2^{2x}(2^{5}-2^{1})\\\\\\3^{2x}(27-9+2)=2^{2x}(32-2)\\\\\\3^{2x}(20)=2^{2x}(30)\\\\\\\dfrac{3^{2x}}{2^{2x}}=\dfrac{30}{20}\to\left(\dfrac{3}{2}\right)^{2x}=\dfrac{3}{2}\to 2x = 1\to x=\dfrac{1}{2}[/tex]