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nathinha6799
@nathinha6799
July 2022
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Calcule o valor de x para que os números (2x; 1-7x; 3x-11) nesta ordem, formem uma P.A.
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kelemen
(1 - 7x) - 2x = r relação I
(3x - 11) - (1 - 7x) = r relação II
fazendo relação I = relação II, temos
(1 - 7x) - 2x = (3x - 11) - (1 - 7x)
1 - 9x = 3x - 11 - 1 + 7x
1 - 9x = 10x - 12
1 + 12 = 19x
19x = 13
x = 13
____
19
Bons Estudos
Kelemen
5 votes
Thanks 11
EdPaitl
[(2x) + (3x – 11)]/2 = (1 - 7x)
[(2x) + (3x – 11)] = 2 . (1 - 7x)
[5x – 11] = 2 - 14x
(5x + 14x) = (2 + 11)
19x = 13
X = 13/19
2 votes
Thanks 3
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Lista de comentários
(3x - 11) - (1 - 7x) = r relação II
fazendo relação I = relação II, temos
(1 - 7x) - 2x = (3x - 11) - (1 - 7x)
1 - 9x = 3x - 11 - 1 + 7x
1 - 9x = 10x - 12
1 + 12 = 19x
19x = 13
x = 13
____
19
Bons Estudos
Kelemen
[(2x) + (3x – 11)] = 2 . (1 - 7x)
[5x – 11] = 2 - 14x
(5x + 14x) = (2 + 11)
19x = 13
X = 13/19