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prue10
@prue10
January 2021
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Bonjour
L eau de javel est une solition aqueuse renfermant des ions hypochlorite clo+,des ions na+,des ions cl- en milieu basique . le pKa du couple HCl/ClO-est egal a 7.3.
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scoladan
Verified answer
Bonjour,
1)
7,3
-----------------------------|----------------------------> pH
HClO ClO⁻
2) si pH = 10,3, l'espèce prédominante est ClO⁻
3) pH = pKa + log([ClO⁻]/|HClO])
4) on en déduit : log([ClO⁻]/[HClO]) = pH - pKa = 10,3 - 7,3 = 3
⇒ [ClO⁻]/[HClO] = 10³
conforme à la réponse à la question 2 : [ClO⁻] = 1000 x [HClO]
Donc [ClO⁻] > [HClO] ⇒ ClO⁻ espèce prédominante
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Verified answer
Bonjour,1)
7,3
-----------------------------|----------------------------> pH
HClO ClO⁻
2) si pH = 10,3, l'espèce prédominante est ClO⁻
3) pH = pKa + log([ClO⁻]/|HClO])
4) on en déduit : log([ClO⁻]/[HClO]) = pH - pKa = 10,3 - 7,3 = 3
⇒ [ClO⁻]/[HClO] = 10³
conforme à la réponse à la question 2 : [ClO⁻] = 1000 x [HClO]
Donc [ClO⁻] > [HClO] ⇒ ClO⁻ espèce prédominante