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lol99
@lol99
June 2021
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Comment résoudre cette équation s'il vous plait !
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jujumy
Verified answer
(x+2)²=121
(x+2)²-121=0
(x+2)²-11² = 0 identité remarquable a²-b²
[ (x+2) -11] [ (x+2)+11] =0
(x+2-11)(x+2+11)= 0
(x-9)(x+13) = 0
x-9=0 ou x+13=0
x = 9 x= -13
S=
{9; -13 }
0 votes
Thanks 1
lol99
merci beaucoup !
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Vous pouvez m'aider pr le 3 s'il vous plait ? Urgence !!!!
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Verified answer
(x+2)²=121(x+2)²-121=0
(x+2)²-11² = 0 identité remarquable a²-b²
[ (x+2) -11] [ (x+2)+11] =0
(x+2-11)(x+2+11)= 0
(x-9)(x+13) = 0
x-9=0 ou x+13=0
x = 9 x= -13
S= {9; -13 }