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annacarol1
@annacarol1
October 2020
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como resolver?
X elevado a dois +6x+9
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3478elc
Verified answer
X² + 6x + 9 = 0
Δ = b² - 4 . a . c
Δ = 6² - 4 . 1 . 9
Δ = 36 - 36
Δ = 0
x = (- b ± √Δ)/(2 . a)
x = (- 6 ± √0)/(2 . 1)
x = (- 6 ± 0)/2
x' = (- 6 + 0)/2
x' = - 6/2
x' = - 3
x'' = (- 6 - 0)/2
x'' = - 6/2
x'' = - 3
S = {- 3}
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Lista de comentários
Verified answer
X² + 6x + 9 = 0Δ = b² - 4 . a . c
Δ = 6² - 4 . 1 . 9
Δ = 36 - 36
Δ = 0
x = (- b ± √Δ)/(2 . a)
x = (- 6 ± √0)/(2 . 1)
x = (- 6 ± 0)/2
x' = (- 6 + 0)/2
x' = - 6/2
x' = - 3
x'' = (- 6 - 0)/2
x'' = - 6/2
x'' = - 3
S = {- 3}