Resposta: letra a) 2

[tex]P= 2y + \frac{5}{3}\\[/tex]

Se [tex]y = \frac{1}{6}[/tex], então

[tex]P = 2*\frac{1}{6} + \frac{5}{3}\\P = \frac{2}{6} + \frac{5}{3} \\P = \frac{1}{3} + \frac{5}{3} \\P = \frac{6}{3} \\P = 2[/tex]