1,28 = 128 x 10⁻² = 2⁷x10⁻²
puisque 2x2x2x2x2x2x2 = 128
on a donc
1,28 x 10⁻⁴ = (2⁷x10⁻²) x 10⁻⁴ = 2⁷x10⁻⁶
et comme 10 = 2x5
on aura 2⁷x(2x5)⁻⁶ = 2⁷x2⁻⁶x5⁻⁶ = 2 x 5⁻⁶
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Verified answer
1,28 = 128 x 10⁻² = 2⁷x10⁻²
puisque 2x2x2x2x2x2x2 = 128
on a donc
1,28 x 10⁻⁴ = (2⁷x10⁻²) x 10⁻⁴ = 2⁷x10⁻⁶
et comme 10 = 2x5
on aura 2⁷x(2x5)⁻⁶ = 2⁷x2⁻⁶x5⁻⁶ = 2 x 5⁻⁶