Démontre que :
[cos(a) + sin(a)] (le tout à carré) = 1 + 2 x cos(a) x sin(a)
[cos(a) + sin(a)] (le tout à carré) = 1 + 2 x cos(a) x sin(a)
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(cosa + sina)² = cos²a + 2sina x cosa + sin²a = (cos²a + sin²a) + 2sina x .cosa= 1 + 2sina x cosa