Derivando a função:
y=(2x-x²).(x³+4x²)
a)y'=(2-2x).(x³+4x²)-(2x-x²).(3x²+8x)
b)y'=(2+2x).(x³+4x²)+(2x+x²).(3x²+8x)
c)y'=(2+2x).(x³+4x²)+(2x-x²).(3x²-8x)
d)y'=(2-2x).(x³+4x²)+(2x-x²).(3x²+8x)

y'=(2-2x).(x³-4x²)+(2x-x²).(3x²-8x)
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