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jessie7
@jessie7
October 2020
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desenvolva o binômio (√x+2)elevado a 6 ( nao tem essa opçao aki kkkk ) pfvv preciso p hj tipo urgente nvdd queria uma resposta agora qlqr um q puder nem precisa ter os calculos so a resposta
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Heberwagner
(√x + 2)⁶ ==>> Binômio de Newton
(6/0)(√x)⁶⁻⁰.2⁶⁻⁰ + (6/1)(√x)⁶⁻¹.2⁶⁻¹ + (6/2)(√x)⁶⁻².2⁶⁻² + (6/3)(√x)⁶⁻³.2⁶⁻³ + (6/4)(√x)⁶⁻⁴.2⁶⁻⁴ + (6/5)(√x)⁶⁻⁵.2⁶⁻⁵ + (6/6)(√x)⁶⁻⁶.2⁶⁻⁶ => (x^1/2*6.2⁶) + (x^1/2*5.2⁵) + (x^1/2*4.2⁴) + + (x^1/2*3.2³) + (x^1/2*2.2²) + (x^1/2*1.2¹) + (x^1/2*0.2⁰) = 64x³ + x^5/2.2⁵ + x^4/2.2⁴ + x^3/2.2³ + x^2/2.2² + x^1/2.2 + x^0/2.2⁰ = 64x³ + 32x²√x + 16x² + 8x√x + 4x + 2√x +1 =
64x³ + 16x² + 4x + 32x²√x + 8x√x + 2√x + 1
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(6/0)(√x)⁶⁻⁰.2⁶⁻⁰ + (6/1)(√x)⁶⁻¹.2⁶⁻¹ + (6/2)(√x)⁶⁻².2⁶⁻² + (6/3)(√x)⁶⁻³.2⁶⁻³ + (6/4)(√x)⁶⁻⁴.2⁶⁻⁴ + (6/5)(√x)⁶⁻⁵.2⁶⁻⁵ + (6/6)(√x)⁶⁻⁶.2⁶⁻⁶ => (x^1/2*6.2⁶) + (x^1/2*5.2⁵) + (x^1/2*4.2⁴) + + (x^1/2*3.2³) + (x^1/2*2.2²) + (x^1/2*1.2¹) + (x^1/2*0.2⁰) = 64x³ + x^5/2.2⁵ + x^4/2.2⁴ + x^3/2.2³ + x^2/2.2² + x^1/2.2 + x^0/2.2⁰ = 64x³ + 32x²√x + 16x² + 8x√x + 4x + 2√x +1 = 64x³ + 16x² + 4x + 32x²√x + 8x√x + 2√x + 1