[tex]( \sqrt{10}) {}^{2} = (x + 2) {}^{2} + x {}^{2} \\ 10 = x {}^{2} + 4x + 4 + x {}^{2} \\ 10 = 2x {}^{2} + 4x + 4 \\ \\ 2x {}^{2} + 4x - 6 = 0( \div 2) \\x {}^{2} + 2x - 3 = 0 \\ \\ Δ = 2 {}^{2} - 4.1. - 3 = 4 + 12 = 16 \\ x1 = \frac{ - 2 + \sqrt{16} }{2} = \frac{ - 2 + 4}{2} = \frac{2}{2} = 1 \\ x2 = \frac{ - 2 - 4}{2} = \frac{ - 6}{2} = - 3[/tex]
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[tex]( \sqrt{10}) {}^{2} = (x + 2) {}^{2} + x {}^{2} \\ 10 = x {}^{2} + 4x + 4 + x {}^{2} \\ 10 = 2x {}^{2} + 4x + 4 \\ \\ 2x {}^{2} + 4x - 6 = 0( \div 2) \\x {}^{2} + 2x - 3 = 0 \\ \\ Δ = 2 {}^{2} - 4.1. - 3 = 4 + 12 = 16 \\ x1 = \frac{ - 2 + \sqrt{16} }{2} = \frac{ - 2 + 4}{2} = \frac{2}{2} = 1 \\ x2 = \frac{ - 2 - 4}{2} = \frac{ - 6}{2} = - 3[/tex]
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