Développer et réduire les expressions suivantes:d(x)=(-2x+1)(x+3)-(x-5) e(x)=(4x+3)(x+1)+(x+1) au carre f(x)=(3x-1)(2x+5)-(x+1)(x-2) SVP merci davance
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Bonjourd(x) =- 2 x - 6 x + x + 3 - x + 5
= - 8 x + 8
e(x) = 4 x² + 4 x + 3 x + 3 + x ² + 2 x + 1
= 5 x² + 10 x + 4
f(x) = 6 x² + 15 x - 2 x - 5 - ( x² - 2 x + x -2)
= 6 x² +13 x - 5 - x² + 2 x - x + 2
= 5 x² +14 x - 3