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Judu13
@Judu13
May 2019
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Développer et réduire : merci de m aider car je n'y arrive pas .
A=(x+4)(x+5)
B=(x-3)(x+8)
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Verified answer
Bonjour,
Méthode à utiliser : (a + b)(c + d) = ac + ad + bc + bd
Exemple : (x + 1)(x + 2) = x² + 2x + x + 2
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nini999
Bonjour :
A = (x + 4)(x + 5)
A = x×x + x×5 + 4×x + 4×5
A = x² + 5x + 4x + 20
A = x² + 9x + 20
B = (x - 3)(x + 8)
B = x² + 8x - 3x - 24
B = x² + 5x - 24
J’espère t'avoir t'aider
1 votes
Thanks 1
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Verified answer
Bonjour,Méthode à utiliser : (a + b)(c + d) = ac + ad + bc + bd
Exemple : (x + 1)(x + 2) = x² + 2x + x + 2
A = (x + 4)(x + 5)
A = x×x + x×5 + 4×x + 4×5
A = x² + 5x + 4x + 20
A = x² + 9x + 20
B = (x - 3)(x + 8)
B = x² + 8x - 3x - 24
B = x² + 5x - 24
J’espère t'avoir t'aider