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Judu13
@Judu13
May 2019
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Développer et réduire: merci de m aider car je n'y arrive pas
C=(2y+1)(y+3)
D=(y-5)(y-2)
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blondinetteoceane88
Verified answer
Bonjour
C=(2y+1)(y+3)
C=2y²+6y+y+3
C=2y²+7y+3
D=(y-5)(y-2)
D=y²-2y-5y+10
D=y²-7y+10
1 votes
Thanks 3
misout1
Verified answer
C= (2y + 1) (y + 3)
= 2y*y + 2y *3 + 1*y + 1*3
= 2y² + 6y + y + 3
=
2y² +7y + 3
D= (y - 5) (y - 2)
= y*y + y*(-2) -5*y -5*(-2)
= y² -2y -5y +10
=
y² -7y + 10
1 votes
Thanks 0
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Lista de comentários
Verified answer
BonjourC=(2y+1)(y+3)
C=2y²+6y+y+3
C=2y²+7y+3
D=(y-5)(y-2)
D=y²-2y-5y+10
D=y²-7y+10
Verified answer
C= (2y + 1) (y + 3)= 2y*y + 2y *3 + 1*y + 1*3
= 2y² + 6y + y + 3
= 2y² +7y + 3
D= (y - 5) (y - 2)
= y*y + y*(-2) -5*y -5*(-2)
= y² -2y -5y +10
= y² -7y + 10