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visigoda
@visigoda
March 2022
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Encontre o valor de X
Obs: Preciso saber como se faz os cálculos.
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araujo1948
VAMOS APLICAR O TEOREMA DE PITAGORAS
(2X+1)² =(2X-1)²+4²
4X²+4X+1=4X²-4X+1+16
4X²+4X+1-4X²+4X-1-16=0
8X-16=0
8X=16
X=16/8
X=2
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(2X+1)² =(2X-1)²+4²
4X²+4X+1=4X²-4X+1+16
4X²+4X+1-4X²+4X-1-16=0
8X-16=0
8X=16
X=16/8
X=2