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Mathildelabest78
@Mathildelabest78
May 2019
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Est ce que vous pouvez m'aidez à a résoudre cette exo j'ai rien compris. Est-ce que vous pouvez m'expliquer ?
Merci
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scoladan
Verified answer
Bonjour,
1) (2x - 2)(x - 5)
= 2x² - 10x - 2x + 10
= 2x² - 12x + 10
= f(x)
2)
(E1) f(x) = 0
⇔ (2x - 2)(x - 5) = 0
⇒ 2x - 2 = 0 ou x - 5 = 0
soit x = 1 ou x = 5
(E2) : f(x) = 10
⇔ 2x² - 12x + 10 = 10
⇔ 2x² - 12x = 0
⇔ 2x(x - 6) = 0
⇒ x = 0 ou x = 6
1 votes
Thanks 1
scoladan
f(-1) = 2 x (-1)^2 - 12 x (-1) + 10 = 2 + 12 + 10 = 24
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Lista de comentários
Verified answer
Bonjour,1) (2x - 2)(x - 5)
= 2x² - 10x - 2x + 10
= 2x² - 12x + 10
= f(x)
2)
(E1) f(x) = 0
⇔ (2x - 2)(x - 5) = 0
⇒ 2x - 2 = 0 ou x - 5 = 0
soit x = 1 ou x = 5
(E2) : f(x) = 10
⇔ 2x² - 12x + 10 = 10
⇔ 2x² - 12x = 0
⇔ 2x(x - 6) = 0
⇒ x = 0 ou x = 6