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yasmineabou
@yasmineabou
June 2021
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Exercice 6 : petit d
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anno32
Bonsoir
a) x² - 6x + 9
identifiant a, b et c
a = 1, b = -6 et c = 9
calculons Δ
Δ = b² - 4ac
Δ = (-6)² - 4(1)(9) = 36 - 36 = 0
x² - 6x + 9
la forme canonique est
(x-3)²
b) 2x² + x + 1
a = 2 b = 1 et c = 1
Calculons Δ
Δ = (1)² - 4(2)(1) = 1 - 8 = -7
Forme canonique
2[(x+1/4)² + 7/16]
c) -3x² + x
a = -3, b = 1 et c = 0
Δ = (1)² - 4(-3)(0) = 1
Forme canonique
-3[(x-1/6)² - 1/36]
d) 2x² - 4x√2 - 7
a = 2, b = 4√2 et c = -7
Δ = (-4√2)² - 4(2)(-7)
Δ = 32 + 56
Δ = 88
Forme canonique
2[(x-√2)² - 88/16]
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Bonjour , j'ai vraiment besoin d'aide c'est niveau 1ere S mais je comprends rien au deux premiers exercice si quelqu'un pourrait m'aider Merciiii bcp
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a) x² - 6x + 9
identifiant a, b et c
a = 1, b = -6 et c = 9
calculons Δ
Δ = b² - 4ac
Δ = (-6)² - 4(1)(9) = 36 - 36 = 0
x² - 6x + 9
la forme canonique est
(x-3)²
b) 2x² + x + 1
a = 2 b = 1 et c = 1
Calculons Δ
Δ = (1)² - 4(2)(1) = 1 - 8 = -7
Forme canonique
2[(x+1/4)² + 7/16]
c) -3x² + x
a = -3, b = 1 et c = 0
Δ = (1)² - 4(-3)(0) = 1
Forme canonique
-3[(x-1/6)² - 1/36]
d) 2x² - 4x√2 - 7
a = 2, b = 4√2 et c = -7
Δ = (-4√2)² - 4(2)(-7)
Δ = 32 + 56
Δ = 88
Forme canonique
2[(x-√2)² - 88/16]