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Bill04
@Bill04
April 2019
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Exercice type-brevet (entrainement)
On pose D= (12x + 3) (2x - 7) - (2x - 7) au carré
1. Développer et réduire D.
2. Factoriser D.
3. Calculer D pour x= 2, puis pour x= -1.
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azert654
1)
D= (12x+3) (2x-7) - (2x-7)²
D= 24x²-84x+6x-21 - (4x²-28x+49)
D= 24x²-84x+6x-21-4x²+28x-49
D=20x²-50x-70
2)
D= (12x+3) (2x-7) - (2x-7)²
D= (2x-7) [(12x+3)-(2x-7)]
D= (2x-7) (12x+3-2x+7)
D= (2x-7) (10x+10)
3)
D= 20x²-50x-70
D= 20*2²-50*2-70
D= 80-100-70
D= -90
D= 20x²-50x-70
D= 20*-1²-50*-1-70
D= 20-50-70
D= -100
Voilà :)
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D= (12x+3) (2x-7) - (2x-7)²
D= 24x²-84x+6x-21 - (4x²-28x+49)
D= 24x²-84x+6x-21-4x²+28x-49
D=20x²-50x-70
2)
D= (12x+3) (2x-7) - (2x-7)²
D= (2x-7) [(12x+3)-(2x-7)]
D= (2x-7) (12x+3-2x+7)
D= (2x-7) (10x+10)
3)
D= 20x²-50x-70
D= 20*2²-50*2-70
D= 80-100-70
D= -90
D= 20x²-50x-70
D= 20*-1²-50*-1-70
D= 20-50-70
D= -100
Voilà :)