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Fillola
@Fillola
June 2021
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Factoriser : Niveau 3eme
bonjour je n'arrive pas a factoriser les calcul suivant :
1) ( x - 1) (x + 2 ) + ( x - 1) ( x + 4 )
2) ( 2x - 1 )² - ( 2x - 1 ) ( x + 3 )
3) x² - 4 + ( x - 2 ) ( 2x + 1 )
4) ( x - 1 )² - 4
5) ( x + 2 )² - ( 3 + 2x )²
Merci de votre aide :-)
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Lista de comentários
guillaume4859
1_(x-1)(x+2+x+s)=(x-1)(2x+6)
=2(x-1)(x+3)
suis lexemple tu arrivera a le faire
0 votes
Thanks 1
Fillola
excuse moi mais je n'ai pas compris comment tu as fait pour la 1.. :/
MissA1
Je note * comme au carre
1)
(x-1)(x+2)+(x-1)(x+4)
(x-1)[(x+2)+(x+4)]
(x-1)[x+2+x+4]
(x-1)(2x+6)
2)
(2x-1)*2-(2x-1)(x+3)
(2x-1)[(2x-1)-(x+3)]
(2x-1)[2x-1-x-3]
(2x-1)(x-4)
3)
x*2-4+(x-2)(2x+1)
x*2-4+2x*2+x-4x-2
3x*2-3x-6
3 (x*2-x-2)
4)
(x-1)*2-4
[(x-1)+2][(x-1)-2]
[x-1+2][x-1-2]
(x+1)(x-3)
5)
(x+2)*2-(3+2x)*2
[(x+2)+(3+2x)][(x+2)-(3+2x)]
[x+2+3+2x][x+2-3-2x]
(3x+5)(-x-1)
1 votes
Thanks 2
Fillola
merci tu me sauves la vie et en décortiquant ce que tu as fait j'ai compris :-) merci beaucoup en tout cas
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Lista de comentários
=2(x-1)(x+3)
suis lexemple tu arrivera a le faire
1)
(x-1)(x+2)+(x-1)(x+4)
(x-1)[(x+2)+(x+4)]
(x-1)[x+2+x+4]
(x-1)(2x+6)
2)
(2x-1)*2-(2x-1)(x+3)
(2x-1)[(2x-1)-(x+3)]
(2x-1)[2x-1-x-3]
(2x-1)(x-4)
3)
x*2-4+(x-2)(2x+1)
x*2-4+2x*2+x-4x-2
3x*2-3x-6
3 (x*2-x-2)
4)
(x-1)*2-4
[(x-1)+2][(x-1)-2]
[x-1+2][x-1-2]
(x+1)(x-3)
5)
(x+2)*2-(3+2x)*2
[(x+2)+(3+2x)][(x+2)-(3+2x)]
[x+2+3+2x][x+2-3-2x]
(3x+5)(-x-1)