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Antoninpamart
@Antoninpamart
May 2019
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J'ai du mal pour la question 1 qi je pouvais avoir des explications merci d'avance
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scoladan
Verified answer
Bonjour,
on donne la formule :
θ = (2,89.10⁶)/λmax - 273
⇔ θ + 273 = (2,89.10⁶)/λmax
⇔ λmax = (2,89.10⁶)/(θ + 273)
Pour une étoile de classe B : 9700 < θ < 24700 ⇒ 9973 < θ + 273 < 24973
Donc : (2,89.10⁶)/24973 < λmax < (2,89.10⁶)/9973
⇔ 289 nm < λmax < 115 nm
Voilà, il faut faire les mêmes calculs pour chaque classe d'étoiles
1 votes
Thanks 1
antoninpamart
merci beaucoup !
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Lista de comentários
Verified answer
Bonjour,on donne la formule :
θ = (2,89.10⁶)/λmax - 273
⇔ θ + 273 = (2,89.10⁶)/λmax
⇔ λmax = (2,89.10⁶)/(θ + 273)
Pour une étoile de classe B : 9700 < θ < 24700 ⇒ 9973 < θ + 273 < 24973
Donc : (2,89.10⁶)/24973 < λmax < (2,89.10⁶)/9973
⇔ 289 nm < λmax < 115 nm
Voilà, il faut faire les mêmes calculs pour chaque classe d'étoiles