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fata
@fata
June 2021
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jai un dm a faire besoin d aide aide moi s il vous plait
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isapaul
Verified answer
Bonsoir
1)
Aire ABCD = 0 si x = 12 car AB = 0
2)
a)
f(x) = (30-x)(12-x)
f(x) = 360 - 30x - 12x + x²
f(x) = x² - 42x + 360
b)
(x-12)(x-40) = x² - 52x + 480
c)
f(x) = 280
x² - 42x + 360 = 280
x² - 42x + 80 = 0
Δ = b²-4ac = 1764 - 320 = 1444 alors √Δ = 38
deux solutions
x' = (-b-√Δ)/2a = (- (- 42) - 38)/2 = (42 - 38)/2 = 2
x" = (- (- 42) +38) / 2 = 40 donc valeur impossible car x ∈ [ 0.8 ; 12 ]
d)
alors au départ on voulait que
f(x) ≥ 280 pour x ≤ 2
f(x) ≥ 280 pour x ∈ [ 0.8 ; 2 ]
Bonne soirée
0 votes
Thanks 1
fata
je peux mettre la dernier partie de cet devoir
fata
c est ca derniere partie http://nosdevoirs.fr/devoir/353781
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Verified answer
Bonsoir1)
Aire ABCD = 0 si x = 12 car AB = 0
2)
a)
f(x) = (30-x)(12-x)
f(x) = 360 - 30x - 12x + x²
f(x) = x² - 42x + 360
b)
(x-12)(x-40) = x² - 52x + 480
c)
f(x) = 280
x² - 42x + 360 = 280
x² - 42x + 80 = 0
Δ = b²-4ac = 1764 - 320 = 1444 alors √Δ = 38
deux solutions
x' = (-b-√Δ)/2a = (- (- 42) - 38)/2 = (42 - 38)/2 = 2
x" = (- (- 42) +38) / 2 = 40 donc valeur impossible car x ∈ [ 0.8 ; 12 ]
d)
alors au départ on voulait que
f(x) ≥ 280 pour x ≤ 2
f(x) ≥ 280 pour x ∈ [ 0.8 ; 2 ]
Bonne soirée