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Leclubdes4
@Leclubdes4
April 2019
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J'ai un doute concernant la factorisation; en effet; j'ai 2 réponses et je ne sais pas laquelle est juste: A= ( x-2)(3x+1)+(3x+1)(4-2x) je fais (3x+1)(x-2+4-2x) (3x+1)(-x+2) ou alors je fais (3x-2)^2+(x-2)(4-2x) : je suis perdue
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nonotata
Verified answer
A = (x-2)(3x+1) +(3x+1)(4-2x)
2 chose (3x+1) est en 2 fois donc ok
donc
tu fais
a = (x-2)(3x+1) +(3x+1)(4-2x)
a = (3x+1)(x-2+4-2x)
a = (3x+1)(-x+2)
0 votes
Thanks 1
nathalienouts
Verified answer
A = (x-2)(3x+1)+(3x+1)(4-2x) tu mets 3x+1 en facteur
A = (3x+1)(x-2+4-2x)
A = (3x+1)(-x+2)
1 votes
Thanks 1
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Je dois factoriser. pouvez vous me corriger (x-2)(3x+1)+(3x+1)(4-2x)= (3x+1)^2(x-2)(4-2x) (3-2x)(4-x)-(3-2x)(5x-7) (3-2x)^2(4-x)(5x-7)
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Lista de comentários
Verified answer
A = (x-2)(3x+1) +(3x+1)(4-2x)2 chose (3x+1) est en 2 fois donc ok
donc
tu fais
a = (x-2)(3x+1) +(3x+1)(4-2x)
a = (3x+1)(x-2+4-2x)
a = (3x+1)(-x+2)
Verified answer
A = (x-2)(3x+1)+(3x+1)(4-2x) tu mets 3x+1 en facteurA = (3x+1)(x-2+4-2x)
A = (3x+1)(-x+2)