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wiamamri
@wiamamri
January 2021
2
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je n'arrive pas à développer et à réduire ses équation
(2t-3)(2t+3)-(2t-3)²
(-x-1)²+(x+1)²
x(3x+2)²-(3x-2)²
aidez moi svp svp
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maudmarine
Verified answer
Bonjour,
(2t-3)(2t+3)-(2t-3)²
= 4t² + 6t - 6t - 9 - (4t² - 12t + 9)
= 4t² - 9 - 4t² + 12t - 9
= 12t - 18
(-x-1)²+(x+1)²
= x² + 2x + 1 + x² + 2x + 1
= 2x² + 4x + 2
x(3x+2)²-(3x-2)²
= x (9x² + 12x + 4) - (9x² - 12x + 4)
= 9x³ + 12x² + 4x - 9x² + 12x - 4
= 9x³ + 3x² + 16x - 4
2 votes
Thanks 0
wiamamri
merci beaucoup
maudmarine
De rien
wiamamri
est ce qu'on doit trouver le résultat ou comme sa sa suffit
hugo12
(2t-3)(2t+3)-(2t-3)
4t²+6t-6t-3-2t+3
4t²-2t+3
1 votes
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Lista de comentários
Verified answer
Bonjour,(2t-3)(2t+3)-(2t-3)²
= 4t² + 6t - 6t - 9 - (4t² - 12t + 9)
= 4t² - 9 - 4t² + 12t - 9
= 12t - 18
(-x-1)²+(x+1)²
= x² + 2x + 1 + x² + 2x + 1
= 2x² + 4x + 2
x(3x+2)²-(3x-2)²
= x (9x² + 12x + 4) - (9x² - 12x + 4)
= 9x³ + 12x² + 4x - 9x² + 12x - 4
= 9x³ + 3x² + 16x - 4
4t²+6t-6t-3-2t+3
4t²-2t+3