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tedis
@tedis
June 2021
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Je n'arrive pas à factoriser D , E et F , et développer E(y) .
Merci
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droopette
(2t+1)²+4t²-1
=(2t+1)(2t+1)+(2t+1)(2t-1)
=(2t+1)(2t+1+2t-1)
=4t(2t+1)
(5x-1)²+10x-2
=(5x-1)(5x-1)+2(5x-1)
=(5x-1)(5x+1+2)
=(5x-1)(5x+3)
x(x+2)-x-2
=x(x+2)-(x+2)1
=(x+2)(x-1)
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tedis
Merci , mais ne saurais-tu développer E(y) ?
tedis
Pourquoi (5x-1)(5x-1)+2(5x-1) est devenu (5x-1)(5x+1+2) avec un + au lieu d'un - (5x-1+2) ?
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Tedis
April 2019 | 0 Respostas
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=(2t+1)(2t+1)+(2t+1)(2t-1)
=(2t+1)(2t+1+2t-1)
=4t(2t+1)
(5x-1)²+10x-2
=(5x-1)(5x-1)+2(5x-1)
=(5x-1)(5x+1+2)
=(5x-1)(5x+3)
x(x+2)-x-2
=x(x+2)-(x+2)1
=(x+2)(x-1)