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LePuceur51100
@LePuceur51100
April 2019
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La question :
Factorise 4x(Carre)-9. En déduire une factorisation de A
A = 4x(Carre)-9 + (2x+3)(x-1)
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MichaelS
Verified answer
4x² - 9 = (2x)² - 3² = (2x-3)(2x+3)
A = 4x² - 9 + (2x+3)(x - 1)
A = (2x-3)(2x+3) + (2x+3)(x-1)
A = (2x+3)(2x-3+x-1)
A = (2x+3)(3x-4)
0 votes
Thanks 1
nonotata
4x²-9
identite remarquable de la forme (a-b)(a+b) =a²-b²
donc
4x²-9
=(2x-3)(2x+3)
A = 4x²-9 + (2x+3)(x-1)
a =(2x-3)(2x+3) +(2x+3)(x-1)
a =(2x+3)(2x-3 +x-1)
a =(2x+3)(3x-4)
0 votes
Thanks 0
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Verified answer
4x² - 9 = (2x)² - 3² = (2x-3)(2x+3)A = 4x² - 9 + (2x+3)(x - 1)
A = (2x-3)(2x+3) + (2x+3)(x-1)
A = (2x+3)(2x-3+x-1)
A = (2x+3)(3x-4)
identite remarquable de la forme (a-b)(a+b) =a²-b²
donc
4x²-9
=(2x-3)(2x+3)
A = 4x²-9 + (2x+3)(x-1)
a =(2x-3)(2x+3) +(2x+3)(x-1)
a =(2x+3)(2x-3 +x-1)
a =(2x+3)(3x-4)