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JustCause
@JustCause
January 2021
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le n*23,aidez moi svp
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MichaelS
Verified answer
Bonsoir,
1)
Dans le triangle ENB rectangle en N : cos(B) = NB/EB
Dans le triangle IHB rectangle en H : cos(B) = HB / IB
2)
D'après la question précédente : NB/EB = HB/IB
3)
IB = (EB x HB) / NB
IB = (6,2 x 0,8) / 3,2
IB = 1,55
1 votes
Thanks 1
JustCause
merci beaucoup
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Verified answer
Bonsoir,1)
Dans le triangle ENB rectangle en N : cos(B) = NB/EB
Dans le triangle IHB rectangle en H : cos(B) = HB / IB
2)
D'après la question précédente : NB/EB = HB/IB
3)
IB = (EB x HB) / NB
IB = (6,2 x 0,8) / 3,2
IB = 1,55