Oie, Td Bom?!
= [(n - 1)!]/[(n + 1)!]
= [(n - 1)!]/[(n + 1) . n . (n - 1)!]
= 1/[(n + 1) . n]
= 1/[n² + n]
= [(n - 1)!]/[(n - 3)!]
= [(n - 1) . (n - 2) . (n - 3)!]/[(n - 3)!]
= (n - 1) . (n - 2)
= n² - 2n - n + 2
= n² - 3n + 2
= [(n + 2)!]/[(n + 1)!]
= [(n + 2) . (n + 1)!]/[(n + 1)!]
= n + 2
Att. Makaveli1996
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Verified answer
A)b)
c)
Oie, Td Bom?!
a)
= [(n - 1)!]/[(n + 1)!]
= [(n - 1)!]/[(n + 1) . n . (n - 1)!]
= 1/[(n + 1) . n]
= 1/[n² + n]
b)
= [(n - 1)!]/[(n - 3)!]
= [(n - 1) . (n - 2) . (n - 3)!]/[(n - 3)!]
= (n - 1) . (n - 2)
= n² - 2n - n + 2
= n² - 3n + 2
c)
= [(n + 2)!]/[(n + 1)!]
= [(n + 2) . (n + 1)!]/[(n + 1)!]
= n + 2
Att. Makaveli1996