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MiissP0MM3
@MiissP0MM3
April 2019
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~Mathématique~
consigne : Développer et réduire si possible les expressions :
a) (3x+4)(2x+9)+(4x+2)(3x+6)
b) (5x-3)(2x+3)-(x+2)(5-x)
c) (4-5x)(-x-7)-(2x-4)(3x-5)
d) (8x+4)(2x-3)+(2x-4)(5x+4)
Merci de m'aider s'il vous plait j'ai vraiment besoin d'aide je n'y arrive absolument pas :/ merci beaucoup
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maudmarine
Verified answer
a) (3x+4)(2x+9)+(4x+2)(3x+6)
= 6x² + 27x + 8x + 36 + 12x² + 24x + 6x + 12
= 6x² + 12x² + 27x + 8x + 24x + 6x + 36 + 12
= 18x² + 65x + 48
b) (5x-3)(2x+3)-(x+2)(5-x)
= 10x² + 15x - 6x - 9 - (5x - x² + 10 - 2x)
= 10x² + 15x - 6x - 9 - 5x + x² - 10 + 2x
= 10x² + x² + 15x + 2x - 6x - 5x - 9 - 10
= 11x² + 6x - 19
c) (4-5x)(-x-7)-(2x-4)(3x-5)
= - 4x + 28 + 5x² + 35x - (6x² - 10x - 12x + 20)
= - 4x + 28 + 5x² + 35x - 6x² + 10x + 12x - 20
= 5x² - 6x² - 4x + 35x + 10x + 12x + 28 - 20
= - x² + 53x + 8
d) (8x+4)(2x-3)+(2x-4)(5x+4)
= 16x² - 24x + 8x - 12 + 10x² + 8x - 20x - 16
= 16x² + 10x² - 24x - 20x + 8x + 8x - 12 - 16
= 26x² - 28x - 28
2 votes
Thanks 1
MiissP0MM3
merci beaucoup !!! tu es bien sur du resultat ?
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Resolvez dans R (3x-2)(6x+1)(5-2x)=0 merci beaucoup
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Exercice d'equation : resolvons dans R : (3-5x)(4x+3)=0. merci beaucoup
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bon jours vous pouvez m'aidez pour la 1,3,5,7,12 svp ? merci c'est pour demain
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Bonsoir , svp aider moi c'est pour demain ...
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Verified answer
a) (3x+4)(2x+9)+(4x+2)(3x+6)= 6x² + 27x + 8x + 36 + 12x² + 24x + 6x + 12
= 6x² + 12x² + 27x + 8x + 24x + 6x + 36 + 12
= 18x² + 65x + 48
b) (5x-3)(2x+3)-(x+2)(5-x)
= 10x² + 15x - 6x - 9 - (5x - x² + 10 - 2x)
= 10x² + 15x - 6x - 9 - 5x + x² - 10 + 2x
= 10x² + x² + 15x + 2x - 6x - 5x - 9 - 10
= 11x² + 6x - 19
c) (4-5x)(-x-7)-(2x-4)(3x-5)
= - 4x + 28 + 5x² + 35x - (6x² - 10x - 12x + 20)
= - 4x + 28 + 5x² + 35x - 6x² + 10x + 12x - 20
= 5x² - 6x² - 4x + 35x + 10x + 12x + 28 - 20
= - x² + 53x + 8
d) (8x+4)(2x-3)+(2x-4)(5x+4)
= 16x² - 24x + 8x - 12 + 10x² + 8x - 20x - 16
= 16x² + 10x² - 24x - 20x + 8x + 8x - 12 - 16
= 26x² - 28x - 28