Réponse :
bonsoir
Explications étape par étape :
1.
1/(x+1) -1/x
on met au même dénominateur
= 1*(x) - 1 (x+1) / [ (x)(x+1)]
= (x -x -1 ) / [ (x)(x+1)]
= -1 / (x² + x )
2)
g(x) = 3/x + x /3
= (3*3 +x*x) / (x*3)
(9 +x²) / (3x)
3)
h(x) = 2(2x-1) - 1 (x-3) / [(x-3)(2x-1)
h(x) = [4x-2 - x+3] / [2x²-x -6x+3]
h(x) = [3x+1] / [2x²-7x +3]
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Réponse :
bonsoir
Explications étape par étape :
1.
1/(x+1) -1/x
on met au même dénominateur
= 1*(x) - 1 (x+1) / [ (x)(x+1)]
= (x -x -1 ) / [ (x)(x+1)]
= -1 / (x² + x )
2)
g(x) = 3/x + x /3
= (3*3 +x*x) / (x*3)
(9 +x²) / (3x)
3)
h(x) = 2(2x-1) - 1 (x-3) / [(x-3)(2x-1)
h(x) = [4x-2 - x+3] / [2x²-x -6x+3]
h(x) = [3x+1] / [2x²-7x +3]