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claraloris39
@claraloris39
October 2020
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O numero natural A e impar e a soma de seus dois algarismos
e 11. A soma dos possiveis valores de A e:
a) 76
b) 103
c) 141
d) 224
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BeatrizPerroni
²65-- 6+5=11
+29-- 2+9=11
83-- 8+3=11
47-- 4+7=11
_____
224
Resposta: Alternativa ( D ).
1 votes
Thanks 4
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[tex] (a^{2} +3b- b^{2}+3a) /a+b[/tex]
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Lista de comentários
+29-- 2+9=11
83-- 8+3=11
47-- 4+7=11
_____
224
Resposta: Alternativa ( D ).