[tex] (a^{2} +3b- b^{2}+3a) /a+b[/tex].... Pergunta de ideia declaraloris39

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[tex] (a^{2} +3b- b^{2}+3a) /a+b[/tex]

$\frac{a^2+3b-b^2+3a}{a+b}=\frac{(a^2-b^2)+3(a+b)}{a+b}=\frac{(a+b)(a-b)+3(a+b)}{a+b}=\frac{(a+b)(a-b+3)}{a+b}=\\
\\
\boxed{a-b+3}$

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claraloris39 Toda vez que tiver, igual no exemplo mais de um (a+b) , passa a ter so um?

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