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h7g9
@h7g9
January 2021
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On considère trois entier consécutifs .
Leslie les calcule le produit du troisième membre par le double du premier .
Jonathan calculer le carré du deuxième nombre auquel il ajoute deux .
Ils obtiennent le même résultat .
Quel sont les entiers choisi au départ?
Merci a ceux ou celle qui m aiderons
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trudelmichel
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BONJOUR.
soit x ; (x+1) (x+2)
Leslie =
(2x)*(x+2)=2x²+4x
Jonathan
(x+1)²+2=x²+1+2x+2=x²+2x+3
alors
2x²+4=x²+2x+3
2x²-x²-2x+4-3=0
x²-2x+1=0
x²-2x+1=(x-1)²
(x-1)²=0
x-1=0x=1
d'où les nombres sont 1;2 et3
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Verified answer
BONJOUR.soit x ; (x+1) (x+2)
Leslie =
(2x)*(x+2)=2x²+4x
Jonathan
(x+1)²+2=x²+1+2x+2=x²+2x+3
alors
2x²+4=x²+2x+3
2x²-x²-2x+4-3=0
x²-2x+1=0
x²-2x+1=(x-1)²
(x-1)²=0
x-1=0x=1
d'où les nombres sont 1;2 et3