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lolita82
@lolita82
January 2021
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Bonjour, (19 points à la clé)
Besoin d'aide pour cet exercice s'il vous plaît.
Exprimer cos (4x) en fonction de cos x et/ou sin x.
Merci d'avance.
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laurance
4x = 2* 2x cos (2x)= 2cos²x -1
cos(4x)= 2cos²(2x) -1 = 2( 2cos²x-1)² - 1
= 2( 4 (cosx)^4 - 4 cos²x + 1) - 1
= 8(cosx)^4 - 8cos²x + 1
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4x = 2* 2x cos (2x)= 2cos²x -1
cos(4x)= 2cos²(2x) -1 = 2( 2cos²x-1)² - 1
= 2( 4 (cosx)^4 - 4 cos²x + 1) - 1
= 8(cosx)^4 - 8cos²x + 1