PERGUNTA 1

Assinale a alternativa que apresenta o determinante da matriz A equals open square brackets table row 2 1 row 1 1 end table close square brackets

a.
det(A) = -1


b.
det(A) = 0


c.
det(A) = π


d.
det(A) = 1
e.
det(A) = 2


1,25 pontos

PERGUNTA 2

Escolha a opção que tem o determinante da matriz A equals open square brackets table row 0 1 0 row 1 1 2 row 1 0 1 end table close square brackets

a.
det(A) = 1

b.
det(A) = π

c.
det(A) = 0

d.
det(A) = 2

e.
det(A) = -1

1,25 pontos

PERGUNTA 3

Escolha a opção que possui o determinante da matriz A equals open square brackets table row 1 1 2 122 row 0 1 62 4 row 0 0 5 7 row 0 0 0 1 end table close square brackets

a.
det(A) = -1

b.
det(A) = 2

c.
det(A) = 1

d.
det(A) = 0

e.
det(A) = 5

1,25 pontos

PERGUNTA 4

Assinale a alternativa que apresenta uma matriz que possui inversa.

a.
A equals open square brackets table row 2 1 row 1 1 end table close square brackets

b.
A equals open square brackets table row 1 2 3 row 2 4 6 row 1 3 0 end table close square brackets

c.
A equals open square brackets table row 1 2 1 row 0 0 0 row 1 1 4 end table close square brackets

d.
A equals open square brackets table row 2 1 row 4 2 end table close square brackets

e.
A equals open square brackets table row 1 2 0 row 2 cell negative 1 end cell 0 row 1 3 0 end table close square brackets

1,25 pontos

PERGUNTA 5

Considere A equals open square brackets table row 2 1 row 1 1 end table close square brackets space e space B equals open square brackets table row 3 2 row 1 5 end table close square brackets.

Assinale a opção correta.

a.
det(AB) = 26

b.
det(AB) = 15

c.
det(AB) = 17

d.
det(AB) = 1

e.
det(AB) = 13

1,25 pontos

PERGUNTA 6

Assinale a opção que possui a inversa da matriz A equals open square brackets table row 2 1 3 row 1 1 3 row 3 3 9 end table close square brackets

a.
A to the power of negative 1 end exponent equals open square brackets table row 3 3 9 row 1 1 3 row 2 1 3 end table close square brackets

b.
A to the power of negative 1 end exponent equals open square brackets table row 1 1 cell 3 over 2 end cell row 1 1 cell 3 over 2 end cell row cell 3 over 2 end cell cell 3 over 2 end cell cell 9 over 2 end cell end table close square brackets

c.
A to the power of negative 1 end exponent equals open square brackets table row cell 1 half end cell 1 cell 1 third end cell row 1 1 cell 1 third end cell row cell 1 third end cell cell 1 third end cell cell 1 over 9 end cell end table close square brackets

d.
A matriz A não tem inversa.

e.
A to the power of negative 1 end exponent equals open square brackets table row 9 3 3 row 3 1 1 row 3 1 2 end table close square brackets

1,25 pontos

PERGUNTA 7

Assinale a opção que possui a inversa da matriz A equals open square brackets table row 3 2 row 1 1 end table close square brackets

a.
A to the power of negative 1 end exponent equals open square brackets table row cell negative 3 end cell cell negative 2 end cell row cell negative 1 end cell cell negative 1 end cell end table close square brackets

b.
A to the power of negative 1 end exponent equals open square brackets table row 1 cell negative 3 end cell row cell negative 1 end cell 2 end table close square brackets

c.
A to the power of negative 1 end exponent equals open square brackets table row 1 cell negative 2 end cell row cell negative 1 end cell 3 end table close square brackets

d.
A to the power of negative 1 end exponent equals open square brackets table row cell 1 third end cell cell 1 half end cell row 1 1 end table close square brackets

e.
A to the power of negative 1 end exponent equals open square brackets table row 1 cell negative 2 end cell row cell negative 1 end cell cell negative 3 end cell end table close square brackets

1,25 pontos

PERGUNTA 8

Escolha a opção que possui o determinante da matriz A equals open square brackets table row 0 1 2 0 1 row 0 0 0 0 0 row 1 2 5 7 1 row 1 1 0 2 1 row 1 0 1 1 1 end table close square brackets

a.
det(A) = π

b.
det(A) = -1

c.
det(A) = 1

d.
det(A) = 2

e.
det(A) = 0