PERGUNTA 1Assinale a alternativa que apresenta o determinante da matriz A equals open square brackets table row 2 1 row 1 1 end table close square bracketsa.det(A) = -1b.det(A) = 0c.det(A) = π d.det(A) = 1e.det(A) = 21,25 pontos PERGUNTA 2Escolha a opção que tem o determinante da matriz A equals open square brackets table row 0 1 0 row 1 1 2 row 1 0 1 end table close square bracketsa.det(A) = 1b.det(A) = π c.det(A) = 0d.det(A) = 2e.det(A) = -11,25 pontos PERGUNTA 3Escolha a opção que possui o determinante da matriz A equals open square brackets table row 1 1 2 122 row 0 1 62 4 row 0 0 5 7 row 0 0 0 1 end table close square bracketsa.det(A) = -1b.det(A) = 2c.det(A) = 1d.det(A) = 0e.det(A) = 51,25 pontos PERGUNTA 4Assinale a alternativa que apresenta uma matriz que possui inversa. a.A equals open square brackets table row 2 1 row 1 1 end table close square bracketsb.A equals open square brackets table row 1 2 3 row 2 4 6 row 1 3 0 end table close square bracketsc.A equals open square brackets table row 1 2 1 row 0 0 0 row 1 1 4 end table close square bracketsd.A equals open square brackets table row 2 1 row 4 2 end table close square bracketse.A equals open square brackets table row 1 2 0 row 2 cell negative 1 end cell 0 row 1 3 0 end table close square brackets1,25 pontos PERGUNTA 5Considere A equals open square brackets table row 2 1 row 1 1 end table close square brackets space e space B equals open square brackets table row 3 2 row 1 5 end table close square brackets.Assinale a opção correta.a.det(AB) = 26b.det(AB) = 15c.det(AB) = 17d.det(AB) = 1e.det(AB) = 131,25 pontos PERGUNTA 6Assinale a opção que possui a inversa da matriz A equals open square brackets table row 2 1 3 row 1 1 3 row 3 3 9 end table close square bracketsa.A to the power of negative 1 end exponent equals open square brackets table row 3 3 9 row 1 1 3 row 2 1 3 end table close square bracketsb.A to the power of negative 1 end exponent equals open square brackets table row 1 1 cell 3 over 2 end cell row 1 1 cell 3 over 2 end cell row cell 3 over 2 end cell cell 3 over 2 end cell cell 9 over 2 end cell end table close square bracketsc.A to the power of negative 1 end exponent equals open square brackets table row cell 1 half end cell 1 cell 1 third end cell row 1 1 cell 1 third end cell row cell 1 third end cell cell 1 third end cell cell 1 over 9 end cell end table close square bracketsd.A matriz A não tem inversa.e.A to the power of negative 1 end exponent equals open square brackets table row 9 3 3 row 3 1 1 row 3 1 2 end table close square brackets1,25 pontos PERGUNTA 7Assinale a opção que possui a inversa da matriz A equals open square brackets table row 3 2 row 1 1 end table close square bracketsa.A to the power of negative 1 end exponent equals open square brackets table row cell negative 3 end cell cell negative 2 end cell row cell negative 1 end cell cell negative 1 end cell end table close square bracketsb.A to the power of negative 1 end exponent equals open square brackets table row 1 cell negative 3 end cell row cell negative 1 end cell 2 end table close square bracketsc.A to the power of negative 1 end exponent equals open square brackets table row 1 cell negative 2 end cell row cell negative 1 end cell 3 end table close square bracketsd.A to the power of negative 1 end exponent equals open square brackets table row cell 1 third end cell cell 1 half end cell row 1 1 end table close square bracketse.A to the power of negative 1 end exponent equals open square brackets table row 1 cell negative 2 end cell row cell negative 1 end cell cell negative 3 end cell end table close square brackets1,25 pontos PERGUNTA 8Escolha a opção que possui o determinante da matriz A equals open square brackets table row 0 1 2 0 1 row 0 0 0 0 0 row 1 2 5 7 1 row 1 1 0 2 1 row 1 0 1 1 1 end table close square bracketsa.det(A) = π b.det(A) = -1c.det(A) = 1d.det(A) = 2e.det(A) = 0