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Abdoulmissoufa
@Abdoulmissoufa
April 2019
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on conserve la 1ere equation et on lq combine avec la deuxieme et la troisieme pour y eliminer x.
c
x+2y-3z=0 ---> 1ere equation
2x+y-z=1---> 2e equation
-3x+y+2z=3 ---> 3e equation.
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kvnmurty
X + 2 y - 3z = 0
l'eq 2 - 2 * l'eq 1 => -3 y + 5z = 1 --- 4 eme eq
l'eq 3 + 3 * l'eq 1 => 7 y -7 z = 3 => y - z = 3/7 -- 5 eme eq
l'eq 4 + 3 * l'eq 5 => 2 z = 16/7 => z = 8/7
on utilisant l'equation 5 , on va obtenir : y = 11/7
la 1ere equation nous donne : x = -2y + 3z = 2/7
x = 2/7, y = 11/7 z = 8/7
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Resolvez dans ir linequation 3x2-2x+1>2. svp urgen
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l'eq 2 - 2 * l'eq 1 => -3 y + 5z = 1 --- 4 eme eq
l'eq 3 + 3 * l'eq 1 => 7 y -7 z = 3 => y - z = 3/7 -- 5 eme eq
l'eq 4 + 3 * l'eq 5 => 2 z = 16/7 => z = 8/7
on utilisant l'equation 5 , on va obtenir : y = 11/7
la 1ere equation nous donne : x = -2y + 3z = 2/7
x = 2/7, y = 11/7 z = 8/7