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Tsurugis
@Tsurugis
May 2019
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Pourriez m'aider avec cet exo svp
x étant la mesure principale d'un angle orienté non droit, démontrer que tan²x-sin²x=tan²xsin²x
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Bonjour,
tan²x - sin²x = tan² x * sin²x
Donc
tan²x - sin²x= sin²x (1/cos² - 1)
= sin²x ((1-cos²x)/ cos²x)
= tan²x* sin²x
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Verified answer
Bonjour,tan²x - sin²x = tan² x * sin²x
Donc
tan²x - sin²x= sin²x (1/cos² - 1)
= sin²x ((1-cos²x)/ cos²x)
= tan²x* sin²x