Articles
Register
Sign In
Search
Tsurugis
@Tsurugis
May 2019
2
64
Report
Pouviez-vous m'aider avec cet exo
Démontrer que:
a) (cosx+sinx)²= 1 + 2cosx sinx
b) (cosx-sinx)²= 1 - 2cosx sinx
c) cos²x+sin²x= 1 - 2cos²x sin²x
N'importe quelle réponse sera précieuse
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
Aeneas
Verified answer
(cosx + sinx)^2 = cosx^2 + sinx^2 + 2cosxsinx = 1 + 2cossinx(cosx - sinx)^2 = cosx^2 + sinx^2 - 2cosxsinx = 1 - 2cossinx
cos²x+sin²x= 1 normalement ...
0 votes
Thanks 0
Stiaen
Verified answer
Bonsoir,
a) (cos x + sin x)²
= cos²x + 2cosx sinx + sin²x
= 1 + 2cosx sinx
→ cos²a + sin²a = 1
→ (a+b)² = a² +2ab + b²
b) (cosx - sinx)²
= cos²x - 2cosx sinx + sin²x
= 1 - 2cosx sinx
→(a-b)² = a²-2ab+b²
c) cos²x + sin²x = 1 !
Erreur dans l'énoncé ??
0 votes
Thanks 0
Stiaen
Cela le change rien
More Questions From This User
See All
Tsurugis
May 2019 | 0 Respostas
Responda
Tsurugis
May 2019 | 0 Respostas
Responda
Tsurugis
May 2019 | 0 Respostas
Responda
Tsurugis
May 2019 | 0 Respostas
Svp veuillez m'aider sur cet exo demontrer que:=0
Responda
Tsurugis
May 2019 | 0 Respostas
Responda
×
Report "Pouviez-vous m'aider avec cet exo Démontrer que: a) (cosx+sinx)²= 1 + 2cosx sinx b) (cosx-sinx)²= 1 .... Pergunta de ideia de Tsurugis"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
(cosx + sinx)^2 = cosx^2 + sinx^2 + 2cosxsinx = 1 + 2cossinx(cosx - sinx)^2 = cosx^2 + sinx^2 - 2cosxsinx = 1 - 2cossinxcos²x+sin²x= 1 normalement ...
Verified answer
Bonsoir,a) (cos x + sin x)²
= cos²x + 2cosx sinx + sin²x
= 1 + 2cosx sinx
→ cos²a + sin²a = 1
→ (a+b)² = a² +2ab + b²
b) (cosx - sinx)²
= cos²x - 2cosx sinx + sin²x
= 1 - 2cosx sinx
→(a-b)² = a²-2ab+b²
c) cos²x + sin²x = 1 !
Erreur dans l'énoncé ??