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Tsurugis
@Tsurugis
May 2019
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Pouviez-vous m'aider avec cet exo
Démontrer que:
a) (cosx+sinx)²= 1 + 2cosx sinx
b) (cosx-sinx)²= 1 - 2cosx sinx
c) cos²x+sin²x= 1 - 2cos²x sin²x
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(cosx + sinx)^2 = cosx^2 + sinx^2 + 2cosxsinx = 1 + 2cossinx(cosx - sinx)^2 = cosx^2 + sinx^2 - 2cosxsinx = 1 - 2cossinx
cos²x+sin²x= 1 normalement ...
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Stiaen
Verified answer
Bonsoir,
a) (cos x + sin x)²
= cos²x + 2cosx sinx + sin²x
= 1 + 2cosx sinx
→ cos²a + sin²a = 1
→ (a+b)² = a² +2ab + b²
b) (cosx - sinx)²
= cos²x - 2cosx sinx + sin²x
= 1 - 2cosx sinx
→(a-b)² = a²-2ab+b²
c) cos²x + sin²x = 1 !
Erreur dans l'énoncé ??
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Verified answer
(cosx + sinx)^2 = cosx^2 + sinx^2 + 2cosxsinx = 1 + 2cossinx(cosx - sinx)^2 = cosx^2 + sinx^2 - 2cosxsinx = 1 - 2cossinxcos²x+sin²x= 1 normalement ...
Verified answer
Bonsoir,a) (cos x + sin x)²
= cos²x + 2cosx sinx + sin²x
= 1 + 2cosx sinx
→ cos²a + sin²a = 1
→ (a+b)² = a² +2ab + b²
b) (cosx - sinx)²
= cos²x - 2cosx sinx + sin²x
= 1 - 2cosx sinx
→(a-b)² = a²-2ab+b²
c) cos²x + sin²x = 1 !
Erreur dans l'énoncé ??