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Alienware
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May 2019
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Pourriez-vous m'aidez ceux qui sont bons en maths je ne comprends pas la loi binomiale pour les 1 ES SVP
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scoladan
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Bonjour,
juste le cours à appliquer : X loi binomiale de paramètres (n;p)
p(X=k) = (Combinaisons de k parmi n) x p^k x (1 - p)^(n - k)
Ici, n = 8 et p = 4/5 ⇒ (1 - p) = 1/5, et k = 3
p(X = 3) = (Combinaisons 3 parmi 8) x (4/5)³ x (1/5)⁵
= 0,0092 arrondi à 10⁻⁴ près
2 votes
Thanks 1
Alienware
merci beaucoup ;)
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Verified answer
Bonjour,juste le cours à appliquer : X loi binomiale de paramètres (n;p)
p(X=k) = (Combinaisons de k parmi n) x p^k x (1 - p)^(n - k)
Ici, n = 8 et p = 4/5 ⇒ (1 - p) = 1/5, et k = 3
p(X = 3) = (Combinaisons 3 parmi 8) x (4/5)³ x (1/5)⁵
= 0,0092 arrondi à 10⁻⁴ près