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natacha3
@natacha3
January 2021
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Pouvez m'aider à comprendre mon devoir maison de maths !
Ecrire comme les babyloniens
l'exercice numéro 92 de la page jointe
merci d'avance
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slyz007
Verified answer
Bonjour
Je note ∀pour le chevron et T pour le clou
1a) ∀∀∀∀ TTTT = 44
∀∀∀∀∀ TT = 52
1b) 17 = ∀ TTTTTTT
39 = ∀∀∀ TTTTTTTTT
Je mets .. pour séparer les multiplicateurs de 60 :
2a) ∀T .. ∀∀TT = 11x60+22=682
∀∀TT .. ∀∀∀TTTTT = 22x60+35=1320+35=1355
2b) 1x3600+17x60+31= T .. ∀TTTTTTT .. ∀∀∀T
187=3x60+7 = TTT .. TTTTTTT
2 votes
Thanks 1
calinizou
Verified answer
Bonjour 1/a 40+4=44
50+2=52
b/ alors j'utilise < pour chevron dizaine et I pour clou unité
< IIII <<< IIIII
III IIII
2/a (10*60)+22
600 +22=622
2235
b/60*60+17*60+31
<<<I+I<IIII I+<<<I
<<< III
187=3*60+7
III I IIII
III (là suis pas trop sure)
1 votes
Thanks 0
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Lista de comentários
Verified answer
BonjourJe note ∀pour le chevron et T pour le clou
1a) ∀∀∀∀ TTTT = 44
∀∀∀∀∀ TT = 52
1b) 17 = ∀ TTTTTTT
39 = ∀∀∀ TTTTTTTTT
Je mets .. pour séparer les multiplicateurs de 60 :
2a) ∀T .. ∀∀TT = 11x60+22=682
∀∀TT .. ∀∀∀TTTTT = 22x60+35=1320+35=1355
2b) 1x3600+17x60+31= T .. ∀TTTTTTT .. ∀∀∀T
187=3x60+7 = TTT .. TTTTTTT
Verified answer
Bonjour 1/a 40+4=4450+2=52
b/ alors j'utilise < pour chevron dizaine et I pour clou unité
< IIII <<< IIIII
III IIII
2/a (10*60)+22
600 +22=622
2235
b/60*60+17*60+31
<<<I+I<IIII I+<<<I
<<< III
187=3*60+7
III I IIII
III (là suis pas trop sure)